20 Rút gọn
a) (2x-y)(2x+y)-(2x+y)^2 ; b) (x-3)(x^2+3x+9)-(5-x)^2
c) (2x+y)(4x^2-2xy+y^2)-(2x+y)^3 ; d) (3x-5)^2-(3x+5)^2
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Những câu hỏi liên quan
9 tháng 7 2018
\(a,\left(2x-y\right)\left(2x+y\right)-\left(2x+y\right)^2\)
\(=4x^2-y^2-4x^2-4xy+y^2\)
\(=-4xy\)
\(b,\left(x-3\right)\left(x^2+3x+9\right)-\left(5-x\right)^2\)
\(=x^3-27-25+10x-x^2\)
\(=x^3-x^2+10x-52\)
\(c,\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x+y\right)^3\)
\(=8x^3+y^3-4x^2-4xy-y^2\)
\(d,\left(3x-5\right)^2-\left(3x+5\right)^2\)
\(=\left(3x-5-3x-5\right)\left(3x-5+3x+5\right)\)
\(=-10.6x=-60x\)
19 tháng 2 2021
a) ( x + 2 )( x2 - 2x + 4 ) - ( 18 + x3 )
= x3 + 8 - 18 - x3 = -10
b) ( 2x - y )( 4x2 + 2xy + y2 ) - ( 2x + y )( 4x2 - 2xy + y2 )
= 8x3 - y3 - ( 8x3 + y3 )
= 8x3 - y3 - 8x3 - y3 = -2y3
c) ( x - 3 )( x + 3 ) - ( x + 5 )( x - 1 )
= x2 - 9 - ( x2 + 4x - 5 )
= x2 - 9 - x2 - 4x + 5 = -4x - 4
d) ( 3x - 2 )2 + ( x + 1 )2 + 2( 3x - 2 )( x + 1 )
= ( 3x - 2 + x + 1 )2
= ( 4x - 1 )2
QA
21 tháng 7 2021
Trả lời:
a, ( 2x + y )3 - ( 2x - y )3
= ( 2x )3 + 3.( 2x )2.y + 3.2x.y2 + y3 - [ ( 2x )3 - 3.( 2x )2.y + 3.2x.y2 - y3 ]
= 8x3 + 12x2y + 6xy2 + y3 - ( 8x3 - 12x2y + 6xy2 - y3 )
= 8x3 + 12x2y + 6xy2 + y3 - 8x3 + 12x2y - 6xy2 + y3
= 24x2y + 2y3
b, ( 5 - 3x )3 - ( 5 + 3x )3
= 53 - 3.52.3x + 3.5.( 3x )2 - ( 3x )3 - [ 53 + 3.52.3x + 3.5.( 3x )2 + ( 3x )3 ]
= 125 - 225x + 135x2 - 27x3 - ( 125 + 225x + 135x2 + 27x3 )
= 125 - 225x + 135x2 - 27x3 - 125 - 225x - 135x2 - 27x3
= - 54x3- 450x
c, ( x + 3 ) ( x2 - 2x + 9 ) - ( 54 + x3 )
= x3 - 2x2 + 9x + 3x2 - 6x + 27 - 54 - x3
= x2 + 3x - 27
d, ( 2x + y ) ( 4x2 - 2xy + y2 ) - 2xy ( 4x2 + 2xy + y2 )
= ( 2x )3 + y3 - 8x3y - 4x2y2 - 2xy3
= 8x3 + y3 - 8x3y - 4x2y2 - 2xy3
NV
4
GP
14 tháng 7 2021
a) (x+3)(x^2-3x+9)-(54+x^3)
= x^3- 3x^2+9x+3x^2-9x+27-54-x63
= -27
b) (2x + y)(4x^2 – 2xy + y^2) – (2x – y)(4x^2+ 2xy + y^2)
= (2x + y)[(2x)^2 – 2x.y + y^2] – (2x – y)[(2x)^2 + 2x.y + y^2]
= [(2x)3^3+ y^3] – [(2x)^3 – y^3]
= (2x)^3 + y^3 – (2x)^3 + y^3
= 2y^3
GS
14 tháng 7 2021
a)(x+3)(X^2-3x+9)-(54+x^3)
= \(x^3\)+ \(3^3 \) - 54 -\(x^3\)
= 27- 54
= -27
b)(2x+y)(4x^2-2xy+y^2)-(2x-y)(4x^2+2xy+y^2)
= \((2x)^3\) + \(y^3\) - [\((2x)^3\) - \(y^3\) ]
= \(8x^3\) + \(y^3\) - \(8x^3\) + \(y^3\)
= \(2y^3\)
8 tháng 6 2019
Tìm x:
1. 3x (2x + 3) - (2x + 5).(3x - 2) = 8
\(\Leftrightarrow6x^2+9x-6x^2+4x-15x+10=0 \)
\(\Leftrightarrow-2x+10=0\Leftrightarrow x=5\)
Vậy x = 5
2. 4x (x -1) - 3(x2 - 5) -x2 = (x - 3) - (x + 4)
\(\Leftrightarrow4x^2-4x-3x^2+15-x^2=x-3-x-4\)
\(\Leftrightarrow-4x+15=-7\)
\(\Leftrightarrow-4x=-22\Leftrightarrow x=\frac{11}{2}\)
Vậy x = \(\frac{11}{2}\)
3. 2 (3x -1) (2x +5) - 6 (2x - 1) (x + 2) = -6
\(\Leftrightarrow2\left(6x^2+15x-2x-5\right)-6\left(2x^2+4x-x-2\right)=-6\)
\(\Leftrightarrow12x^2+30x-4x-10-12x^2-24x+6x+12=-6\)
\(\Leftrightarrow8x=-8\Leftrightarrow x=-1\)
Vậy x = -1
4. 3 ( 2x - 1) (3x - 1) - (2x - 3) (9x - 1) - 3 = -3
\(\Leftrightarrow3\left(6x^2-2x-3x+1\right)-18x^2+2x+27x-3-3=-3\)
\(\Leftrightarrow18x^2-6x-9x+3-18x^2+2x+27x-6=-3\)
\(\Leftrightarrow14x=0\Leftrightarrow x=0\)
Vậy x = 0
5. (3x - 1) (2x + 7) - ( x + 1) (6x - 5) = (x + 2) - (x - 5)
\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5=7\)
\(\Leftrightarrow18x=9\Leftrightarrow x=\frac{1}{2}\)
Vậy x = \(\frac{1}{2}\)
6. 3xy (x + y) - (x + y) (x2 + y2 + 2xy) + y3 = 27
\(\Leftrightarrow3x^2y+3xy^2-\left(x+y\right)^3+y^3=27\)
\(\Leftrightarrow3x^2y+3xy^2-x^3-y^3-3x^2y-3xy^2+y^3=27\)
\(\Leftrightarrow-x^3=27\)
\(\Leftrightarrow x=-3\)
Vậy x = -3
7. 3x (8x - 4) - 6x (4x - 3) = 30
\(\Leftrightarrow24x^2-12x-24x^2+12x=30\)
\(\Leftrightarrow0=30\) ( vô lý)
Vậy pt vô nghiệm
8. 3x (5 - 2x) + 2x (3x - 5) = 20
\(\Leftrightarrow15x-6x^2+6x^2-10x=20\)
\(\Leftrightarrow5x=20\Leftrightarrow x=4\)
Vậy x = 4
TC
1
17 tháng 9 2017
b) \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)
\(=\left(2x+y\right)\left(4x^2-2xy+y^2\right)+\left(2x+y\right)\left(4x^2+2xy+y^2\right)\)
\(=\left(2x+y\right)\left(4x^2-2xy+y^2+4x^2+2xy+y^2\right)\)
\(=\left(2x+y\right)\left(8x^2+2y^2\right)\)
\(=\left(2x+y\right)\left(4x+y\right).2xy\)
15 tháng 8 2017
Bài 2 :
Câu a : \(y\left(y^3+y^2-y-2\right)-\left(y^2-2\right)\left(y^2+y+1\right)\)
\(=y^4+y^3-y^2-2y-y^4-y^3-y^2+2y^2+2y+2\)
\(=2\) \(\Rightarrow\) ko phụ thuộc vào biến .
Câu b : \(\left(2x+3\right)\left(4x^2-6x+9\right)-2\left(4x^3-1\right)\)
\(=8x^3-12x^2+18x+12x^2-18x+27-8x^3+2\)
\(=29\Rightarrow\) ko thuộc vào biến
Câu c : \(3x\left(x+5\right)-\left(3x+18\right)\left(x-1\right)\)
\(=3x^2+15x-3x^2+3x-18x+18\)
\(=18\) \(\Rightarrow\) ko thuộc vào biến
Câu d : \(\left(2x+6\right)\left(4x^2-12x+36\right)-8x^3+5\)
\(=8x^3-24x^2+72x+24x^2-72x+216-8x^3+5\)
\(=221\) \(\Rightarrow\) không thuộc vào biến
16 tháng 8 2017
câu 1) a) \(\left(x^2+2xy+y^2\right)\left(x+y\right)=\left(x+y\right)^2\left(x+y\right)=\left(x+y\right)^3\)
b) \(y\left(y^3+y^2-3y-2\right)+\left(y^2-2\right)\left(y^2+y-1\right)\)
\(=y^4+y^3-3y^2-2y+y^4+y^3-y^2-2y^2-2y+2\)
\(=2y^4+2y^3-6y^2-4y+2=2y\left(y^3+y^2-3y-2\right)+2\)
\(=2y\left(y+2\right)\left(y^2-y-1\right)+2=2\left(y^2+2y\right)\left(y^2-y-1\right)+2\)
\(=2\left(y^2+2y\right)\left(y^2-y-1+1\right)=2\left(y^2+2y\right)\left(y^2-y\right)\)
c) \(6x^2-\left(2x+5\right)\left(3x-2\right)=6x^2-\left(6x^2-4x+15x-10\right)\)
\(\Leftrightarrow6x^2-6x^2+4x-15x+10=-11x+10\)
d) \(\left(2x-1\right)\left(3x+1\right)+\left(3x+4\right)\left(3-2x\right)\)
\(\)\(=6x^2+2x-3x-1+9x-6x^2+12-8x=11\)
e) \(\left(3x-5\right)\left(7-5x\right)-\left(5x+2\right)\left(2-3x\right)\)
\(=21x-15x^2-35+25x-\left(10x-15x^2+4-6x\right)\)
\(21x-15x^2-35+25x-10x+15x^2-4+6x=42x-39\)
a) (2x-y)(2x+y)-(2x+y)^2
= 4x2-y2-(4x2+4xy+y2)
= 4x2-y2-4x2-4xy-y2
= -4xy
b) (x-3)(x^2+3x+9)-(5-x)^2
= (x3-27)-(25-10x+x2)
= x3-27-25+10x-x2
= x3-x2+10x-52
c) (2x+y)(4x^2-2xy+y^2)-(2x+y)^3
= (2x)3+y3- ((2x)3+3.4x2.y+3.y2.2x+y3)
= 8x3+y3-(8x3+12x2y+6xy2+y3)
= 8x3+y3-(8x3+12x2y+6xy2+y3)
= 8x3+y3-8x3-12x2y-6xy2-y3
=-12x2y-6xy2
d) (3x-5)^2-(3x+5)^2
= (3x-5-3x-5)(3x-5+3x+5)
= -10.6x
= -60x